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Time & Work

Work-rate problems including pipes & cisterns and combined effort.

6%
of Quant

Why This Topic Matters

Total PYQs📊
20
of 1002 · 2021–2025
Years featured📅
5/5
of recent CAT years
% of Quant📈
~6%
of section questions
Est. hours⏱️
~10h
to master
2/22
2021
1/22
2022
~2/22
2023
1/22
2024
1/22
2025
🎯PYQ Evidence

CAT 2021–2025: ~1.3 per slot (2021: 2.0 · 2022: 1.0 · 2023: 1.7 · 2024: 1.0 · 2025: 1.0). Every year without fail — efficiency-ratio and pipes-style framings dominate.

Time & Work

Think in rates, not hours. If someone finishes a job in nn days, their rate is 1n\dfrac1n of the job per day. Rates add when people work together — that single idea solves almost every question here, including pipes and cisterns.

Core results

  • Combined rate: 1a+1b\dfrac1a+\dfrac1b; time together =aba+b=\dfrac{ab}{a+b}.
  • Work–rate constant: M1D1H1W1=M2D2H2W2\dfrac{M_1 D_1 H_1}{W_1}=\dfrac{M_2 D_2 H_2}{W_2} (men × days × hours per unit of work).
  • Pipes & cisterns: inflow is positive, a leak is negative — just add the signed rates.
  • Efficiency ↔ time are inversely proportional: twice as efficient ⇒ half the time.

A worked example

A finishes a job in 12 days, B in 18 days. Working together, how long do they take?

Add the rates:

112+118=336+236=536 job/day  time=365=7.2 days.\frac1{12}+\frac1{18}=\frac{3}{36}+\frac{2}{36}=\frac{5}{36}\ \text{job/day}\ \Rightarrow\ \text{time}=\frac{36}{5}=\mathbf{7.2\text{ days}}.

LCM trick: let the total work be lcm(12,18)=36\operatorname{lcm}(12,18)=36 units. Then A does 3 units/day, B does 2, together 5 units/day, so 36/5=7.236/5=7.2 days — no fractions at all.

🎯PYQ Evidence
Make the job a fixed pile of units, then count what each worker adds. : take total work as LCM(15,12,20) = 60 units so every rate is a whole number (4, 5, 3 per day); since the team repeats a two-day block of 9 + 8 = 17 units, three blocks give 51 and day 7 finishes the last 9. : fix the job at LCM of the person-hour totals (120 units), convert to units/hour, and the "double" conditions collapse to one equation 4(2d) + 12d = 120, so Seema works 6 days. : set the slowest worker's rate to 1 unit/day and scale up (2 and 4); summing each phase's rate × days gives 140 + 200 = 340 units, which Chandan alone clears in 340 days. The whole family reduces to: pick units so rates are integers, then total work = rate × time added across phases.

Common traps

  • Adding times instead of rates. 12+1812+18 means nothing; rates add, times don't.
  • Forgetting a leak. A draining pipe subtracts from the fill rate.
  • Partial work. If A leaves midway, account for the work already done before adding B's contribution.

Checklist

  • Convert every worker to a rate (job per day)
  • Add rates for simultaneous work; subtract for leaks
  • Use the LCM-of-times = total units trick to kill fractions
  • Keep efficiency ∝ 1/time in mind for "twice as fast" phrasing

Sample Questions

13 practice questions

Medium

Machine A and Machine B produce 1 widget in 3 hours together. If Machine A's speed were doubled, they could produce 1 widget in 2 hours. How many hours does Machine A currently take alone?

Easy

A copy machine makes 35 copies per minute and a second makes 55 copies per minute. Working together, how many copies do they make in half an hour?

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CAT PYQ Spotlight

Actual CAT questions on this topic

CAT 2025 · Slot 1
Hard

Arun, Varun and Tarun, if working alone, can complete a task in 24, 21, and 15 days, respectively. They charge Rs 2160, Rs 2400, and Rs 2160 per day, respectively, even if they are employed for a partial day. On any given day, any of the workers may or may not be employed to work. If the task needs to be completed in 10 days or less, then the minimum possible amount, in rupees, required to be paid for the entire task is

CAT 2024 · Slot 1
TITAHard

Renu would take 15 days working 4 hours per day to complete a certain task whereas Seema would take 8 days working 5 hours per day to complete the same task. They decide to work together. Seema agrees to work for double the number of hours per day as Renu, while Renu agrees to work for double the number of days as Seema. If Renu works 2 hours per day, then the number of days Seema will work, is

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